metawho.Rmd
The goal of metawho is to provide simple R implementation of “Meta-analytical method to Identify Who Benefits Most from Treatments” (called ‘deft’ approach, see reference #2).
metawho is powered by R package metafor and does not support dataset contains individuals for now. Please use stata package ipdmetan if you are more familar with stata code.
This is a basic example which shows you how to solve a common problem.
If you have HR and confidence intervals, please run deft_prepare()
firstly.
library(metawho)
### specify hazard ratios (hr)
hr <- c(0.30, 0.11, 1.25, 0.63, 0.90, 0.28)
### specify lower bound for hr confidence intervals
ci.lb <- c(0.09, 0.02, 0.82, 0.42, 0.41, 0.12)
### specify upper bound for hr confidence intervals
ci.ub <- c(1.00, 0.56, 1.90, 0.95, 1.99, 0.67)
### specify sample number
ni <- c(16L, 18L, 118L, 122L, 37L, 38L)
### trials
trial <- c("Rizvi 2015", "Rizvi 2015",
"Rizvi 2018", "Rizvi 2018",
"Hellmann 2018", "Hellmann 2018")
### subgroups
subgroup = rep(c("Male", "Female"), 3)
entry <- paste(trial, subgroup, sep = "-")
### combine as data.frame
wang2019 =
data.frame(
entry = entry,
trial = trial,
subgroup = subgroup,
hr = hr,
ci.lb = ci.lb,
ci.ub = ci.ub,
ni = ni,
stringsAsFactors = FALSE
)
wang2019 = deft_prepare(wang2019)
Here we can directly load example data.
library(metawho)
data("wang2019")
wang2019
#> entry trial subgroup hr ci.lb ci.ub ni
#> 1 Rizvi 2015-Male Rizvi 2015 Male 0.30 0.09 1.00 16
#> 2 Rizvi 2015-Female Rizvi 2015 Female 0.11 0.02 0.56 18
#> 3 Rizvi 2018-Male Rizvi 2018 Male 1.25 0.82 1.90 118
#> 4 Rizvi 2018-Female Rizvi 2018 Female 0.63 0.42 0.95 122
#> 5 Hellmann 2018-Male Hellmann 2018 Male 0.90 0.41 1.99 37
#> 6 Hellmann 2018-Female Hellmann 2018 Female 0.28 0.12 0.67 38
#> conf_q yi sei
#> 1 1.959964 -1.2039728 0.6142831
#> 2 1.959964 -2.2072749 0.8500678
#> 3 1.959964 0.2231436 0.2143674
#> 4 1.959964 -0.4620355 0.2082200
#> 5 1.959964 -0.1053605 0.4030005
#> 6 1.959964 -1.2729657 0.4387290
Use deft_do()
function to obtain model results.
# The 'Male' is the reference
(res = deft_do(wang2019, group_level = c("Male", "Female")))
#> $all
#> $all$data
#> entry trial subgroup hr ci.lb ci.ub ni
#> 1 Rizvi 2015-Male Rizvi 2015 Male 0.30 0.09 1.00 16
#> 2 Rizvi 2015-Female Rizvi 2015 Female 0.11 0.02 0.56 18
#> 3 Rizvi 2018-Male Rizvi 2018 Male 1.25 0.82 1.90 118
#> 4 Rizvi 2018-Female Rizvi 2018 Female 0.63 0.42 0.95 122
#> 5 Hellmann 2018-Male Hellmann 2018 Male 0.90 0.41 1.99 37
#> 6 Hellmann 2018-Female Hellmann 2018 Female 0.28 0.12 0.67 38
#> conf_q yi sei
#> 1 1.959964 -1.2039728 0.6142831
#> 2 1.959964 -2.2072749 0.8500678
#> 3 1.959964 0.2231436 0.2143674
#> 4 1.959964 -0.4620355 0.2082200
#> 5 1.959964 -0.1053605 0.4030005
#> 6 1.959964 -1.2729657 0.4387290
#>
#> $all$model
#>
#> Fixed-Effects Model (k = 6)
#>
#> Test for Heterogeneity:
#> Q(df = 5) = 18.8865, p-val = 0.0020
#>
#> Model Results:
#>
#> estimate se zval pval ci.lb ci.ub
#> -0.3207 0.1289 -2.4883 0.0128 -0.5733 -0.0681 *
#>
#> ---
#> Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
#>
#>
#>
#> $subgroup
#> $subgroup$data
#> trial hr ci.lb ci.ub ni conf_q yi
#> 1 Rizvi 2015 0.3666667 0.0469397 2.8641945 34 1.959964 -1.003302
#> 2 Rizvi 2018 0.5040000 0.2805772 0.9053338 240 1.959964 -0.685179
#> 3 Hellmann 2018 0.3111111 0.0967900 1.0000013 75 1.959964 -1.167605
#> sei
#> 1 1.0487893
#> 2 0.2988460
#> 3 0.5957285
#>
#> $subgroup$model
#>
#> Fixed-Effects Model (k = 3)
#>
#> Test for Heterogeneity:
#> Q(df = 2) = 0.5657, p-val = 0.7536
#>
#> Model Results:
#>
#> estimate se zval pval ci.lb ci.ub
#> -0.7956 0.2589 -3.0737 0.0021 -1.3030 -0.2883 **
#>
#> ---
#> Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
#>
#>
#>
#> attr(,"class")
#> [1] "deft"
Use deft_show()
to visualize results.
To show all entries without model result.
To show result of subgroup analysis.
The analysis above reproduced Figure 5 of reference #1.
The result of deft_do()
contains models constructed by metafor package, so you can use features provided by metafor package, e.g. plot the model results with forest()
function from metafor package.
Modify plot, more see ?forest.rma
.
forest(res$subgroup$model, showweights = TRUE, atransf = exp,
slab = res$subgroup$data$trial,
xlab = "Hazard ratio")
op = par(no.readonly = TRUE)
par(cex = 0.75, font = 2)
text(-11, 4.5, "Trial(s)", pos = 4)
text(9, 4.5, "Hazard Ratio [95% CI]", pos = 2)
More usage about model fit, prediction and plotting please refer to metafor package.